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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3843/CH2/EX2.3/Ex2_3.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3843/CH2/EX2.3/Ex2_3.sce')
| -rw-r--r-- | 3843/CH2/EX2.3/Ex2_3.sce | 18 |
1 files changed, 18 insertions, 0 deletions
diff --git a/3843/CH2/EX2.3/Ex2_3.sce b/3843/CH2/EX2.3/Ex2_3.sce new file mode 100644 index 000000000..52e7dd4f3 --- /dev/null +++ b/3843/CH2/EX2.3/Ex2_3.sce @@ -0,0 +1,18 @@ +// Example 2_3
+clc;funcprot(0);
+// Given data
+m=4;// The mass of water in kg
+P=220;// kPa
+x=0.8;// The quality of steam
+
+// Calculation
+// Use Table C-2.To determine the appropriate numbers at 220 kPa we linearly interpolate between 0.2 and 0.3 MPa.
+P_1=0.2*10^3;// kPa
+P_2=0.3*10^3;// kPa
+v_g1=0.8857;// m^3/kg
+v_g2=0.6058;// m^3/kg
+v_g=(((P-P_1)/(P_2-P_1))*(v_g2-v_g1))+v_g1;// m^3/kg
+v_f=0.0011;// m^3/kg
+v=v_f+(x*(v_g-v_f));// m^3/kg
+V=m*v;// The total volume occupied in m^3
+printf("\nThe final volume occupied by the mixture,V=%1.3f m^3",V);
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