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+// Example 11_5

+clc;funcprot(0);

+// Given data

+T=25;// °C

+P=100;// kPa

+V=150;// m^3

+phi=60/100;// The relative humidity at state 1

+P_g=3.169;// kPa

+M_v=18;// kg/k.mol

+M_a=28.97;// kg/k.mol

+R_a=0.287;// kJ/kg.K

+

+// Calculation

+// (a)

+P_v=P_g*phi;// kPa

+P_a=P-P_v;// The partial pressure of air in kPa

+w=0.622*(P_v/P_a);// The humidity ratio in kg H2O/kg dry air

+// (b)

+// From psychrometric chart

+T_dp=16.6;// The dew point temperature in °C

+// (c)

+m_v=w*((P_a*V)/(R_a*(T+273)));// The mass of water vapor in kg

+// (d)

+N_v=m_v/M_v;// mol

+N_a=((P_a*V)/(R_a*(T+273)))/M_a;// mol

+y_v=N_v/(N_a+N_v);// The mole fraction of the water vapor 

+printf("\n(a)The humidity ratio,w=%0.5f kg H2O/kg dry air \n(b)The dew point temperature,T_dp=%2.1f°C \n(c)The mass of water vapor,m_v=%1.2f kg \n(d)The mole fraction of the water vapor,y=%0.4f",w,T_dp,m_v,y_v);