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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3835/CH9/EX9.8/Ex9_8.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3835/CH9/EX9.8/Ex9_8.sce')
-rw-r--r-- | 3835/CH9/EX9.8/Ex9_8.sce | 26 |
1 files changed, 26 insertions, 0 deletions
diff --git a/3835/CH9/EX9.8/Ex9_8.sce b/3835/CH9/EX9.8/Ex9_8.sce new file mode 100644 index 000000000..b5e6ba3f0 --- /dev/null +++ b/3835/CH9/EX9.8/Ex9_8.sce @@ -0,0 +1,26 @@ +clear +// +//given +i=35 +v=220 +ra=0.15 +n1=1600 +//when motor is running at 1200rpm the back emf eb1 is given by eb1=v-(35*0.15) +eb1=214.75 +//flux phy1 is proportional to armature current ia.Thus, at ia1=35 and ia2=15 n is proportional to eb/phy +//2=(eb2*phy1)/(phy2*eb1) +//therefore +eb2=184.07 +//case a +//resistance to be connected in series is rse ohm +ia2=15 +rse=((v-eb2)/ia2)-ra +printf("\n rse= %0.1f ohm",rse) +//case b +eb2=0.5*1.15*214.75 +ia2=50 +rse=((v-eb2)/ia2)-ra +phy1=35 +eb2=220-50*0.15 +n2=(n1*eb2*phy1)/(1.15*phy1*eb1) +printf("\n n2= %0.1f rpm",n2) |