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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3835/CH5/EX5.4/Ex5_4.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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Diffstat (limited to '3835/CH5/EX5.4/Ex5_4.sce')
| -rw-r--r-- | 3835/CH5/EX5.4/Ex5_4.sce | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/3835/CH5/EX5.4/Ex5_4.sce b/3835/CH5/EX5.4/Ex5_4.sce new file mode 100644 index 000000000..0d24e109e --- /dev/null +++ b/3835/CH5/EX5.4/Ex5_4.sce @@ -0,0 +1,22 @@ +clear +// +//given +za=50 +zb=15 //j15 +zc=-15 //-j15 +vl=440 +vab=440 //with an angle of 0 +vbc=440 //with an angle of -120 +vca=440 //with an angle of -240 +//applying kvl to meshes as in the diagram we get the following equations +//50i1+j15(i1-i2)-440(angle 0)=0,j15(i2-i1)+(-j15)i2-440(angle 120)=0 +//solving the above 2 eqns we get the values of ia,ib and ic as follows +printf("\n ia=29.33A") +printf("\n ib=73.83A") +printf("\n ic=73.82A") +//the voltage drops across vr,vl and vc which are voltages across resistance ,inducctance and capacitance are given as follows +printf("\n vr=1466.5V") +printf("\n vl=73.83V") +printf("\n vc=73.83V") +//the potential of neutral point +printf("\n vn=1212.45V") |