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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 7_2
+clc;funcprot(0);
+// Given data
+T_L=10;// °C
+W_E=5.00;// MW
+W_P=100;// kW
+Q_L=8.00;// MW
+
+// Solution
+// (a)
+Q_H=abs(-Q_L)+(W_E-abs(-W_P/10^3));// MW
+n_T=((W_E-abs(-W_P/10^3))/Q_H);// The actual thermal efficiency of the power plant
+printf('\nThe actual thermal efficiency of the power plant,n_T=%2.1f percentage',n_T*100);
+// (b)
+T_H=(T_L+273.15)/(1-n_T);// K
+T_H=T_H-273.15;// °C
+printf('\nThe equivalent heat source temperature,T_H=%3.0f°C',T_H);