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+// Example 5_7

+clc;funcprot(0);

+// Given data

+D=0.100;// m

+T_1=200;// °C

+p_1=0.140;// MPa

+h=3.50;// W/(m^2.K)

+T_infinitive=15.0;// °C

+c_v=3.123;// kJ/kg.K

+R=2.077;// kJ/kg.K

+t=5.00;// seconds

+

+// Calculation

+V=(%pi/6)*D^3;// m^3

+A=%pi*D^2;// m^2

+m=((p_1*10^3)*V)/(R*(T_1+273.15));// kg

+hAbymc_v=(h*A)/(m*c_v*1000);// s^-1

+T_2=((T_1-T_infinitive)*exp((-(h*A)/(m*c_v*1000))*t))+T_infinitive;// °C

+delU=m*c_v*(T_2-T_1);// kJ

+printf('\n(a)The final temperature of the helium,T_2=%2.1f°C \n(b)The change in total internal energy of the helium,U_2-U_1=%0.3f kJ',T_2,delU);