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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 19_6
+clc;funcprot(0);
+// Given data
+rho=996;// kg/m^3
+Q=8.70;// J/s
+T=30+273;// K
+k_t=0.610;// J/(s.K.m)
+k_o=1.91;// m^2/s
+k_p=1.00*10^-12;// m^2
+mu=891*10^-6;// kg/(s.m)
+dx=0.100;// m
+
+// Solution
+m=(rho*Q)/((T*(k_t/k_o))+(mu*(k_o/k_p)));// kg/s
+dTbydx=-(T*m)/(rho*k_o);// K/m
+dT=dTbydx*dx;// K
+printf('\nThe induced isobaric mass flow rate,m=%1.2e kg/s \nThe resulting temperature difference between the vessels,dT=%1.2e K',m,dT);