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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 18_7
+clc;funcprot(0);
+// Given data
+N=10;// The number of available students
+R=5;// The number of ordered groups
+
+// Calculation
+// (a)
+P_a=(factorial(N))/(factorial(N-R));// P_using each student only once
+// (b)
+P_b=N^R;// P_using each student more than once
+// (c)
+P_c=(factorial(N))/(factorial(N-R)*factorial(R));// C_using each student only once
+// (d)
+P_d=(factorial(N+R-1))/(factorial(N-1)*factorial(R));// C_using each student more than once
+// (e)
+R_1=4;
+R_2=6
+P_e=(factorial(N))/((factorial(R_1))*(factorial(R_2)));
+printf("\n(a)P_using each student only once=%5.0f groups \n(b)P_using each student more than once=%5.0f groups \n(c)C_using each student only once=%3.0f groups \n(d)C_using each student more than once=%4.0f groups \n(e)P_4,6=%3.0f groups",P_a,P_b,P_c,P_d,P_e);