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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 11_17
+clc;funcprot(0);
+// Given data
+m_A=1.00;// lbm
+p_A=1.00;// psia
+T_A=200;// °F
+m_B=5.00;// lbm
+p_B=5.00;// psia
+T_B=400;// °F
+
+// Calculation
+T_2=((m_A*(T_A+459.67))+(m_B*(T_B+459.67)))/(m_A+m_B);// R
+T_2=T_2-459.67;// °F
+p_2=((m_A+m_B)*(T_2+459.67))/(((m_A*(T_A+459.67))/p_A)+((m_B*(T_B+459.67))/p_B));// psia
+printf("\nThe final temperature,T_2=%3.0f°F \nThe final pressure,p_2=%1.2f psia",T_2,p_2);