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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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+// Exa 5.4
+
+clc;
+clear;
+
+// Given
+
+// The Lissajous pattern
+Y2 = 2.5; // slope of the major axis(in div)
+Y1 = 1.2; // slope of the vertical axis(in div)
+
+// Solution
+
+printf(' The phase shift V2 and V1 can be given as sin(Theta) = Y1/Y2 \n -where V1 and V2 are voltages applied to X and Y axis respectively \n ');
+
+Theta = asind(Y1/Y2) ;
+printf(' Since, the ellipse is lying in the I and the III quadrant, \n The angle is theta or 360-theta , i.e, %.2f or %.2f \n',Theta,360-Theta);