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author | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
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committer | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
commit | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch) | |
tree | 449d555969bfd7befe906877abab098c6e63a0e8 /3830/CH5/EX5.4/Ex5_4.sce | |
parent | d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff) | |
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Diffstat (limited to '3830/CH5/EX5.4/Ex5_4.sce')
-rw-r--r-- | 3830/CH5/EX5.4/Ex5_4.sce | 17 |
1 files changed, 17 insertions, 0 deletions
diff --git a/3830/CH5/EX5.4/Ex5_4.sce b/3830/CH5/EX5.4/Ex5_4.sce new file mode 100644 index 000000000..24ab7b7b6 --- /dev/null +++ b/3830/CH5/EX5.4/Ex5_4.sce @@ -0,0 +1,17 @@ +// Exa 5.4
+
+clc;
+clear;
+
+// Given
+
+// The Lissajous pattern
+Y2 = 2.5; // slope of the major axis(in div)
+Y1 = 1.2; // slope of the vertical axis(in div)
+
+// Solution
+
+printf(' The phase shift V2 and V1 can be given as sin(Theta) = Y1/Y2 \n -where V1 and V2 are voltages applied to X and Y axis respectively \n ');
+
+Theta = asind(Y1/Y2) ;
+printf(' Since, the ellipse is lying in the I and the III quadrant, \n The angle is theta or 360-theta , i.e, %.2f or %.2f \n',Theta,360-Theta);
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