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author | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
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committer | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
commit | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch) | |
tree | 449d555969bfd7befe906877abab098c6e63a0e8 /3830/CH1/EX1.7/Ex1_7.sce | |
parent | d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff) | |
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Diffstat (limited to '3830/CH1/EX1.7/Ex1_7.sce')
-rw-r--r-- | 3830/CH1/EX1.7/Ex1_7.sce | 26 |
1 files changed, 26 insertions, 0 deletions
diff --git a/3830/CH1/EX1.7/Ex1_7.sce b/3830/CH1/EX1.7/Ex1_7.sce new file mode 100644 index 000000000..55aa7af4a --- /dev/null +++ b/3830/CH1/EX1.7/Ex1_7.sce @@ -0,0 +1,26 @@ +// Formulae's from Example 1.6 are used here
+// Exa 1.7
+
+clc;
+clear;
+
+// Given
+
+// Referring circuit given in Fig. 1.23
+Rm = 1000; // Meter resistance in Ohms
+Im = 100*10^-6; // Meter current in Amp
+I1 = 1; // im Amp
+I2 = 0.1; // in Amp
+I3 = 10; // in Amp
+
+// Solution
+
+n = I3/I2;
+Rsh = Rm/(n-1);
+Rc = (Im/I2)*(Rsh+Rm);
+Rb = Rc - (Im/I1)*(Rsh+Rm);
+Ra = Rsh-(Rb+Rc);
+
+printf('The Values of Ra, Rb and Rc are %.2f Ohms, %.2f Ohms and %.2f Ohms respectively \n',Ra,Rb,Rc);
+
+//The answer provided in the textbook is wrong for Ra
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