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author | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
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committer | prashantsinalkar | 2018-02-03 11:01:52 +0530 |
commit | 7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch) | |
tree | 449d555969bfd7befe906877abab098c6e63a0e8 /3830/CH1/EX1.4/Ex1_4.sce | |
parent | d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff) | |
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Diffstat (limited to '3830/CH1/EX1.4/Ex1_4.sce')
-rw-r--r-- | 3830/CH1/EX1.4/Ex1_4.sce | 26 |
1 files changed, 26 insertions, 0 deletions
diff --git a/3830/CH1/EX1.4/Ex1_4.sce b/3830/CH1/EX1.4/Ex1_4.sce new file mode 100644 index 000000000..c646177d7 --- /dev/null +++ b/3830/CH1/EX1.4/Ex1_4.sce @@ -0,0 +1,26 @@ +// Exa 1.4
+
+clc;
+clear;
+
+// Given
+
+S = 10*10^3; // Sensitivity of voltmeter in Ohms/Volt
+V = 75; // Reading in Volts
+Vmax = 100; // Max voltage in Volts
+I = 1.5*10^-3; // reading in Amp
+
+// Solution
+
+printf('Consider Fig.1.10, it shows Rm as meter of voltmeter drawing some current \n Thus, loading of the source happens i.e, loading effect \n');
+Rapparent = V/I;
+Rm = Vmax * S;
+// Rapparent = parallel combination of Rm and Rx
+// Therefore Rx can be given as
+Rx = (1/Rapparent - 1/Rm)^-1;
+printf(' True value of Rx = %.2f K Ohms \n',Rx);
+
+Error = 100* (Rx-Rapparent)/Rx ; // Error in percent
+printf(' The percentage error due to loading effect = %.1f percent \n',Error);
+
+//The answers vary due to round off error
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