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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+////Chapter 13 Steam Engines
+////Example 13.11 Page No 290
+///Find Actual mean effective pressure
+//Input data
+clc;
+clear;
+D=240*10^-3; //Steam engine bor
+L=300*10^-3; //Stroke of engine
+N=220; //Speed of engine 220 in rpm
+IP=36; //Indicated power in Kw
+Pb=1.3; //Exhaust pressure in bar
+re=2.5; //Expansion ratio
+K=0.8; //Diagram factor
+pi=3.142
+A=((pi/4)*(D^2));
+
+
+
+//Calculation
+Pma=((IP*60000)/(2*10^5*L*A*N)); //Indicated power of steam engine in bar
+Pm=Pma/K; //Actual mean effective pressure in bar
+P1=((Pm+Pb)*re)/(1+log(re)); //Theoretical mean effective pressure in bar
+
+//Output
+printf('Indicated power of steam engine= %f bar \n',Pma);
+printf('Actual mean effective pressure= %f bar \n',Pm);
+printf('theoretical mean effective pressure= %f bar \n',P1);