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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3819/CH4/EX4.22/Ex4_22.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3819/CH4/EX4.22/Ex4_22.sce')
| -rw-r--r-- | 3819/CH4/EX4.22/Ex4_22.sce | 24 |
1 files changed, 24 insertions, 0 deletions
diff --git a/3819/CH4/EX4.22/Ex4_22.sce b/3819/CH4/EX4.22/Ex4_22.sce new file mode 100644 index 000000000..34a337ba5 --- /dev/null +++ b/3819/CH4/EX4.22/Ex4_22.sce @@ -0,0 +1,24 @@ +// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal
+// Chapter 4-Buoyancy and Floatation
+//// Problem 4.22
+
+//Given Data Set in the Problem
+dens=1000
+g=9.81
+T=10
+I=10000
+BG=1.5
+W=29430*10^3
+SG=10100
+
+//calculations
+Vol=W/SG //vol of water displaced
+//for meta centric height
+GM=I/Vol-(BG)
+//Using the formula to calculate th eradius of gyration
+function [f]=F(K)
+ f=T-2*%pi*(K^2/GM/g)^0.5
+endfunction
+K=1
+K=fsolve(K,F)
+mprintf("The Radius of gyration is %f m \n",K)
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