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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3819/CH3/EX3.12/Ex3_12.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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-rw-r--r-- | 3819/CH3/EX3.12/Ex3_12.sce | 31 |
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diff --git a/3819/CH3/EX3.12/Ex3_12.sce b/3819/CH3/EX3.12/Ex3_12.sce new file mode 100644 index 000000000..6c469146d --- /dev/null +++ b/3819/CH3/EX3.12/Ex3_12.sce @@ -0,0 +1,31 @@ +// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal
+// Chapter 3-Hydrostatic Forces on surfaces
+// Problem 3.12
+
+//Data given in the Problem
+d=0.6
+a=1.5
+SG=0.9
+dens=1000
+g=9.81
+
+//Calculations
+dens1=SG*dens
+h=a-d
+pA=0
+pD=dens1*g*h
+pB=dens1*g*h+dens*g*d
+//In the diagram,DE=pD,BC=pB,FC=pB-pD
+
+//1)Total pressure
+F1=(1/2*h*pD)*a
+F2=(d*pD)*a
+F3=(1/2*d*(pB-pD))*a
+F=F1+F2+F3
+mprintf("The total pressure is %f N\n",F)
+
+//2) Position of Centre of Pressure
+h=(F1*d+F2*(a-d/2)+(F3*(a-d+2/3*d)))/F //Taking moments of all forces
+mprintf("The position of centre of pressure is %f m from A ",h)
+
+
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