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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3819/CH2/EX2.7/Ex2_7.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3819/CH2/EX2.7/Ex2_7.sce')
| -rw-r--r-- | 3819/CH2/EX2.7/Ex2_7.sce | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/3819/CH2/EX2.7/Ex2_7.sce b/3819/CH2/EX2.7/Ex2_7.sce new file mode 100644 index 000000000..e61848c8c --- /dev/null +++ b/3819/CH2/EX2.7/Ex2_7.sce @@ -0,0 +1,22 @@ +// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal
+// Chapter 2 - Pressure and its measurements
+// Problem 2.7
+
+//Given Data Set in the Problem
+d=3
+a=%pi/4*d^2
+D=10
+A=%pi/4*D^2
+f=80
+dens=1000
+g=9.81
+
+//Calculations
+//When pistons are at same level
+F=f/a*A
+mprintf("The force on the large piston in level with the small piston is %f N\n",F)
+
+//When smaller piston is 40 cm above tha large piston
+p=(dens*g*40/100)/10^4 //pressure due to 40 cm of the liquid
+F_=(f/a+p)*A
+mprintf("The force on the large piston 40 cm below small piston is %f N\n",F_)
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