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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3819/CH2/EX2.26/Ex2_26.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3819/CH2/EX2.26/Ex2_26.sce')
| -rw-r--r-- | 3819/CH2/EX2.26/Ex2_26.sce | 20 |
1 files changed, 20 insertions, 0 deletions
diff --git a/3819/CH2/EX2.26/Ex2_26.sce b/3819/CH2/EX2.26/Ex2_26.sce new file mode 100644 index 000000000..b4b63b578 --- /dev/null +++ b/3819/CH2/EX2.26/Ex2_26.sce @@ -0,0 +1,20 @@ +// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal
+// Chapter 2 - Pressure and its measurements
+// Problem 2.19
+
+//Given Data Set in the Problem
+dens=1000
+g=9.81
+Z=5000
+p0=10.143*10^4
+t0=15
+T0=t0+273.15
+dens0=1.285
+L=-0.0065
+
+//calculations
+R=p0/(dens0*T0)
+//we know L=dT/dZ=-g(k-1)/(Rk)
+k=g/(L*R+g)
+p=p0*(1-(k-1)/k*g*Z*dens0/p0)^(k/(k-1))
+mprintf("The pressure when air follows adiabatic law is %f N/cm^2\n",p*10^-4)
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