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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3819/CH1/EX1.28/Ex1_28.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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-rw-r--r-- | 3819/CH1/EX1.28/Ex1_28.sce | 23 |
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diff --git a/3819/CH1/EX1.28/Ex1_28.sce b/3819/CH1/EX1.28/Ex1_28.sce new file mode 100644 index 000000000..514384741 --- /dev/null +++ b/3819/CH1/EX1.28/Ex1_28.sce @@ -0,0 +1,23 @@ +// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal
+// Chapter 1-Properties of Fluid
+// Problem 1.28
+
+//Given Data Set in the Problem
+d=2.5*10^-3
+st_w=0.0725
+st_m=0.52
+SG_m=13.6
+dens_w=1000
+dens_m=13.6*1000
+g=9.81
+
+//Calculations
+//Using rise=4*surface tension/(density *g *diameter of capillary)
+//CAPILLARY RISE FOR WATER (theta =0,cos 0=1)
+h=4*st_w/(dens_w*g*d)
+mprintf("The rise for water is %f cm \n",h*100)
+
+//CAPILLARY RISE FOR MERCURY
+//Using rise=4*surface tension/(density *g *diameter of capillary)
+h=4*st_m*cos(%pi*130/180)/(dens_m*g*d)
+mprintf("The rise for mercury is %f cm",h*100)
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