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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3819/CH1/EX1.27/Ex1_27.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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-rw-r--r-- | 3819/CH1/EX1.27/Ex1_27.sce | 15 |
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diff --git a/3819/CH1/EX1.27/Ex1_27.sce b/3819/CH1/EX1.27/Ex1_27.sce new file mode 100644 index 000000000..6fa16b3b2 --- /dev/null +++ b/3819/CH1/EX1.27/Ex1_27.sce @@ -0,0 +1,15 @@ +// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal
+// Chapter 1-Properties of Fluid
+// Problem 1.27
+
+//Given Data Set in the Problem(SI Units)
+d=0.04*10^-3
+p_outside=10.32*10^4
+st=0.0725
+
+//Calculations
+//Using pressure =(4*Surface tension)/(diameter of the droplet)
+p=4*st/d
+//But this pressure obtained is p_inside-p_outside thus,
+p_inside=p_outside+p
+mprintf("The pressure inside the droplet is %f n/cm^2",p_inside*10^-4);
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