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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3819/CH1/EX1.17/Ex1_17.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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diff --git a/3819/CH1/EX1.17/Ex1_17.sce b/3819/CH1/EX1.17/Ex1_17.sce new file mode 100644 index 000000000..e297a278c --- /dev/null +++ b/3819/CH1/EX1.17/Ex1_17.sce @@ -0,0 +1,23 @@ +// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal
+// Chapter 1-Properties of Fluid
+// Problem 1.17
+
+
+//Given Data Set in the Problem(SI Units)
+d=15/100
+d_outer=15.10/100
+l=25/100
+T=12
+N=100
+
+
+//Calculations
+u_tang=%pi*d*N/60
+Area_surface=%pi*d*l
+du=u_tang-0
+dy=(d_outer-d)/2
+ //We know, Shear stress=Force/Area=viscosity*(Velocity Gradient)
+ //also, Torque=Force*Diameter/2.......or.. Force=(Torque*2)/Diameter
+ //hence, 2*Torque/(diameter*area)=Viscosity*(Vel. gradient)
+visc=2*T/(d*Area_surface*du/dy)
+mprintf("The Viscosity of the liquid is %f poise",visc*10)
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