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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi
+//chapter 3
+//example 3.15
+//edition 1
+//publisher and place:Nelson Engineering
+clc;
+clear;
+Vs=110;//source voltage in volts
+Vdc=150;//DC voltage in volts
+Vm=Vs*2^(1/2);//maximum voltage in volts
+alphamin=0;//triggering angle in degree
+R=1;//resistance in ohm
+Beta=180;//The value of bete
+gama=Beta-alphamin;//conduction period in degree
+VRrms=sqrt(Vdc^(2)+((Vs*2^(1/2))^(2)/2)-((4*Vdc*Vm)/%pi));
+VRrms=ceil(VRrms)
+Idrms=VRrms/R;
+mprintf("\nThe total rms current during discharging is %f A",Idrms)
+a1=((Vm/(R*%pi))*(((1-cosd(2*Beta))/2)-((1-cosd(2*alphamin))/2)))-(((2*Vdc)/(R*%pi))*(sind(Beta)-sind(alphamin)));
+b1=((4*Vdc)/(R*%pi))-(Vm/R);
+pie1=atand(a1/b1);
+I1drms=sqrt((a1^2+b1^2)/2);//rms value of fundamental component
+Pac=Vs*I1drms*cosd(pie1);
+Pac=Pac*10^(-3);
+mprintf("\nThe power delivered to the ac source during discharging is %f kW",Pac)