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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Chapter 18, Example 18.3
+clc
+//Initialisation
+VCC=10 //voltage
+R2=10*10**3 //resistance in ohm
+R1=27*10**3 //resistance in ohm
+RE=1*10**3 //resistance in ohm
+RC=2.2 //resistance in ohm
+VBE=0.7 //base emitter voltage
+
+
+
+//Calculation
+VB=VCC*(R2/(R1+R2)) //Quiescent base voltage
+VE=VB-VBE //Quiescent emitter voltage
+IE=VE/RE //Quiescent emitter current
+IC=IE //Quiescent collector current
+VO=VCC-(IC*RC) //Quiescent collector voltage
+
+
+
+
+//Results
+printf("Quiescent base voltage = %.2f V\n",VB)
+printf("Quiescent emitter voltage = %d V\n",VE)
+printf("Quiescent emitter current = %d mA\n",IE*1000)
+printf("Quiescent collector current = %d mA\n",IC*1000)
+printf("Quiescent collector voltage = %.1f V\n",VO) //wrong answer on textbook