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+//Book Name:Fundamentals of Electrical Engineering

+//Author:Rajendra Prasad

+//Publisher: PHI Learning Private Limited

+//Edition:Third ,2014

+

+//Ex1_11.sce.

+clc;

+clear;

+R=10;         //resistance in ohms

+L=5;          //inductance in henry

+V=100;        //supply voltage in volts

+t1=2;        //time at which k1 switch opened in seconds

+//CASE1

+printf("\n (a)")

+i=(V*(1-exp(-((R*t1)/L))))/R;

+printf("\n  The inductive current at the time k1 is opened=%1.2f A",i)

+

+//CASE2

+printf("\n (b)")

+v1=V*exp(-((R*t1))/L);

+printf("\n  The voltage across the inductor at t=2second=%1.2f V",v1)

+

+//CASE3

+printf("\n (c)")

+t2=3;     //time in seconds

+Imax=(V/R); 

+v2=Imax*R*(exp(-((R*t2))/L));

+printf("\n  The voltage across the inductor at t=3 second=%1.4f V",v2)

+//For v2 calculation ,the answer in the book is wrong

+

+//CASE4

+printf("\n (d)")

+t3=0;   //initial time in seconds

+it=(-R*(-Imax)*exp(-(R*t3)/L))/L;    //rate of decay of inductor current in amphere per seconds

+printf("\n  The initial value of rate of decay of inductor current=%d A/s",it)

+

+//CASE5

+printf("\n (e)")

+Energy=(1/2)*L*Imax^2;

+printf("\n  The energy dissipated in the resistor=%d J",Energy)