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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3792/CH3/EX3.14 | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3792/CH3/EX3.14')
-rw-r--r-- | 3792/CH3/EX3.14/Ex3_14.sce | 18 |
1 files changed, 18 insertions, 0 deletions
diff --git a/3792/CH3/EX3.14/Ex3_14.sce b/3792/CH3/EX3.14/Ex3_14.sce new file mode 100644 index 000000000..02efc42ef --- /dev/null +++ b/3792/CH3/EX3.14/Ex3_14.sce @@ -0,0 +1,18 @@ +// SAMPLE PROBLEM 3/14
+clc;clear;funcprot(0);
+// Given data
+F=800;// lb
+v=4;/// ft/sec
+P=6;// The power output of the winch in hp
+P_i=8;// hp
+theta=30;// degree
+g=32.2;// The acceleration due to gravity in ft/sec^2
+
+// Calculation
+N=F*cosd(theta);// lb
+// SigmaF_x=0;
+T=(P*550)/v;// The tension in the cable in N
+mu_k=(T-(F*sind(theta)))/N;// The coefficient of kinetic friction
+T=(P_i*550)/v;// lb
+a=(T-(N*mu_k)-(F*sind(theta)))*(g/F);// The acceleration in ft/sec^2
+printf("\nThe corresponding instantaneous acceleration of the log,a=%2.2f ft/sec^2",a);
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