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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3785/CH2/EX2.9/Ex2_9.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3785/CH2/EX2.9/Ex2_9.sce')
| -rw-r--r-- | 3785/CH2/EX2.9/Ex2_9.sce | 18 |
1 files changed, 18 insertions, 0 deletions
diff --git a/3785/CH2/EX2.9/Ex2_9.sce b/3785/CH2/EX2.9/Ex2_9.sce new file mode 100644 index 000000000..fa92c6172 --- /dev/null +++ b/3785/CH2/EX2.9/Ex2_9.sce @@ -0,0 +1,18 @@ +// Example 2_9
+clc;funcprot(0);
+// Given data
+// From table 2.1
+z=5;// Altitude in km
+z_i=0;// The initial height in km
+dTbydz=-6.5;// The temperature gradient from 0 to 5 km in K/km
+T_i=288.15;// Temperature in K
+p_i=1.0133*10^5;// Pressure in Pa
+R=287;// Gas constant in J/kg.K
+
+//Calculation
+// Using equation 2.41,
+T=T_i+((dTbydz)*(z-z_i));// Temperature in K
+// Using equation 2.42,
+p=p_i*(T/T_i)^(-1/((dTbydz*10^-3)*29.26));// The pressure in Pa
+rho=p/(R*T);// The density in kg/m^3
+printf("\nT=%0.1f K \np=%1.4e Pa \nrho=%0.4f kg/m^3",T,p,rho);
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