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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+//variable Initialisation
+V=415//Voltage Input in Volts
+f=50//supply frequency in Hz
+P=4//No of Poles
+N1=1450//Rotor Speed in rpm
+N2=1290//Rotor Speed in rpm for case II
+R1=1.01
+R2=0.69
+X1=1.08
+X2=1.60
+Xm=36
+Tl=42//Rated torque in N-m
+//Solution
+Vph=V/sqrt(3)
+Ns=120*f/P
+Ws=2*%pi*Ns/60
+Wm=2*%pi*N1/60
+K=Tl/(Wm^2)
+s=(Ns-N2)/Ns//Slip
+Wm2=Ws*(1-s)
+Tl=K*(Wm2^2)//Load Torque in N-m
+Tl2=Tl*Wm2//Torque in Synchronous Watts
+I2=sqrt((Tl2*s)/(3*R2*(1-s)))
+Z=R1+(R2/s)+(%i*(X1+X2))//Impedance at slip s
+V2=I2*abs(Z)//Voltage applied in Volts/Phase
+Im=V2/(%i*Xm)
+Im1=abs(Im)
+Ir=V2/Z//Rotor Current
+Is=Ir+Im//Stator Current
+a=atand(imag(Is)/real(Is))
+Pin=3*V2*abs(Is)*cosd(a)//Input Power
+Smax=1/3//Smax is obtain theorotically
+I2max=Ws*sqrt(Smax)*(1-Smax)*sqrt(K*Ws/(3*R2))
+Nr=Ns*(1-Smax)//Speed at maximum Current
+Wmax=2*%pi*Nr/60
+T=3*(I2max^2)*R2*(1-Smax)/(Smax*Wmax)//Torque at maximum Current
+printf('\n\n The Load torque=%0.1f N-m\n\n',Tl)
+printf('\n\n The Rotor Current=%0.1f Amp\n\n',Ir)
+printf('\n\n The Stator Supply Voltage=%0.1f Volts\n\n',V2)
+printf('\n\n The Motor input current=%0.1f Amp\n\n',Is)
+printf('\n\n The Motor input power=%0.1f Watt\n\n',Pin)//The answer provided in the textbook is wrong
+printf('\n\n Maximum rotor Current=%0.1f Amp\n\n',I2max)
+printf('\n\n The speed at maximum current=%0.1f rad/sec\n\n',Wmax)
+printf('\n\n The torque at maximum current=%0.1f N-m\n\n',T)