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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+//variable Initialisation
+Vm=240 //Terminal Voltage Of Motor In Volt
+F=50 //Supply Frequency Of Motor
+P=4 //Number Of Pole
+R1=0.25 //Resistance Of Motor in Ohm
+R2=0.60 //Resistance Of Motor in Ohm
+X1=0.36//Reactance in Ohm
+X2=0.36//Reactance in Ohm
+Xm=17.3//Reactance In Ohm
+Nr1=1400 //Speed Of Rotor In RPM
+Nr2=600 //Speed Of Rotor In RPM
+
+//Solution
+#Case=1
+W=((2*%pi)/60)*(Nr1)
+Ns=(120*F)/(P)
+S1=(Ns-Nr1)/Ns
+S2=(Ns-Nr2)/Ns
+Zr=(R2/S1)+%i*(X2)
+Zs=R1+%i*(X1)
+Zt=Zr+Zs
+Zin=(%i*(Xm)*(Zt))/(%i*(Xm)+(Zt))
+Tl=1.4*((10)^-3)*(W)^2
+n=Nr1/60
+I2=sqrt((S1*Tl*2*%pi*n)/(3*R2*(1-S1)))
+#Case=2
+Zr1=(R2/S2)+%i*(X2)
+Zs1=R1+%i*(X1)
+Zt1=Zr1+Zs1
+Zin1=(%i*(Xm)*(Zt1))/(%i*(Xm)+(Zt1))
+W1=((2*%pi)/60)*(Nr2)
+Tl1=1.4*((10)^-3)*(W1)^2
+n1=Nr2/60
+I3=sqrt((S2*Tl1*2*%pi*n1)/(3*R2*(1-S2)))
+//Given base currents in Amp
+Ib1=17.55
+Ib2=100.27
+Ip1=I2/Ib1
+Ip2=I3/Ib2
+printf('\n\n The per unit rotor Current for case 1=%0.1f\n\n',Ip1)
+printf('\n\n The per unit rotor Current for case 2=%0.1f\n\n',Ip2)