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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+//variable initialisation
+Vm=400 //Rated Voltage of motor in volt
+Vs=440 //Supply Voltage of motor in volt
+F=50 //Supply frequency in hrtz
+P=4 //Number Of Poles
+N1=1475 //Speed OF Motor In rpm
+R1=0.35 //Resistance of stator in ohm
+R2=0.18 //Resistance of rotor in ohm
+X1=0.9 //Reactance of Motor in ohm
+X2=0.7 //Reactance of Motor in ohm
+Xm=25 //Reactance of Motor in ohm
+
+//Solution
+Vph1=Vs/(sqrt(3))
+Vph2=Vm/(sqrt(3))
+Ns=(120*F)/(P)
+S=(Ns-N1)/Ns
+I2=(Vph2)/sqrt(((R1+(R2/S))^2)+((X1+X2)^2))
+Pg=3*(I2^2)*(R2/S)
+Sm=R2/sqrt((R1)^2+((X1+X2)^2))
+Wms=(2*%pi*Ns)/60
+Tm=3*(Vph1^2)/((2*Wms)*(R1+sqrt((R1)^2+((X1+X2)^2))))
+Zi=%i*(Xm*((R1+(R2/S))+%i*(X1+X2)))/(R1+(R2/S)+%i*(X1+X2+Xm))
+Z=abs(Zi)
+printf('\n\n The Slip=%0.1f\n\n',S)
+printf('\n\n The Air gap Power Angle=%0.1f Watts\n\n',Pg)
+printf('\n\n The Slip for maximum torque=%0.1f\n\n',Sm)
+printf('\n\n The Maximum Torque=%0.1f N-m\n\n',Tm)
+printf('\n\n The Input Impedance=%0.1f\n\n',Z)
+//The answers vary due to round off error