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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+//Variable Initialisation
+Ea=230//Input Voltage of motor in volts
+d1=0.4//Duty Ratio
+Ia1=86//Armature Current in Ampere
+Ra=0.25//Armature resistance in ohm
+N1=850//Rated Speed of Motor in rpm
+N4=1300//Rated Speed of Motor in rpm
+Eb1=220//Average Value of Back EMF
+//Solution
+E01=d1*Ea
+Eb2=E01+(Ia1*Ra)
+N2=(Eb2/Eb1)*N1
+dmax=0.98//Maximum aloowable duty ratio
+E02=dmax*Ea
+Eb3=E02+(Ia1*Ra)
+N3=(Eb3/Eb1)*N1//Wrong value of N1 is taken in textbook
+Eb4=(N4/N1)*Eb1
+R=((Eb4-E02)/Ia1)-Ra
+E1=(N1/N4)*Eb3
+n=E1/Eb1
+printf('\n\n Motor speed=%0.1f rpm\n\n',N2)
+printf('\n\n Maximum allowable motor Speed=%0.1f rpm\n\n',N3)//The answer provided in the textbook is wrong
+printf('\n\n Resistance to be inserted=%0.1f ohm\n\n',R)
+printf('\n\n number of turns reduced to fraction=%0.1f\n\n',n)