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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+//Variable Initialisation
+Ra=0.08//Armature resistance in ohm
+Rb=1.5
+Rf=12
+N=500//Rated Speed of Motor in rpm
+//Solution
+If0=poly(0,'If0')
+Eb0=poly(0,'Eb0')
+
+If=[4.16,6.2,8.33,10.5,12.5,14.6,16.6,18.8,20]
+Eb=[41.6,61.2,75,85,92,96.6,101,105,125]
+W=2*%pi*N/60
+Ia=((Rb+Rf)/Rb)*If0
+K=Eb0*(1/W)
+If1=12.6
+Eb1=102.2
+for If0=If1
+ disp(Ia)
+end
+for Eb0=Eb1
+ disp(K)
+end
+If2=12.6
+K2=1.75
+Eb2=102.2
+K1=Eb2*(1/W)
+Ia2=9*If2
+Eb3=(If2*Rf)+(Ia2*Ra)//Wrongly calculated in book
+N2=Eb3*60/(K1*2*%pi)
+printf('\n\n Motor Speed at which load is hold by motor=%0.1f rpm\n\n',N2)//The answer provided in the textbook is wrong