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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+//Variable Initialisation
+Ea=220//Input Voltage of motor in volts
+Ia=100//Armature Current in Ampere
+Ia2=1.5*Ia
+Ra=0.01//Armature resistance in ohm
+Rb=2
+N1=1000//Rated Speed of Motor in rpm
+N2=500//Rated Speed of Motor in rpm
+d2=0.5
+//Solution
+Eb1=Ea-(Ia*Ra)
+Eb2=(N2/N1)*Eb1
+d=(1-(((Eb2/Ia2)-Ra)/Rb))//Wrongly solved in textbook
+Eb3=Ia2*(((1-d2)*Rb)+Ra)
+N3=(Eb3/Eb1)*N1
+printf('\n\n Duty Ratio of chopper=%0.1f\n\n',d)//The answer provided in the textbook is wrong
+printf('\n\n Motor Speed=%0.1f rpm\n\n',N3)