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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+// Variable Initialization
+Vm=250//Supply Voltage in Volts
+Ra=0.3//Combined Field and Armature circuit resistance in Ohm
+N=900 //Motor speed in Rpm
+V=220//Rated voltage of motor in Volts
+a=30//firing angle in Degree
+Kaf=0.03 //Constant in N-m/A^2
+Kres=0.075 //Constant in V-s/Rad
+
+//Solution
+W=(2*%pi*N)/60 //angular speed in Rad/sec
+Ia=(((Vm*1.414)/%pi)*(1+cosd(a))-(Kres*W))*(1/(Ra+Kaf*W))//Armature current in Amp
+T=Kaf*(Ia)^2//Torque in N-m
+I=(T/Kaf)^(1/2)//motor current in Amp
+//The motor Terminal voltage would be given by the output voltage of the converter
+Va=(Vm*1.414)*(1+cosd(a))*(1/%pi)//Output voltage in Volts
+
+//Results
+printf('\n\n The motor Torque =%0.1f N-m \n\n',T)
+printf('\n\n The motor Current =%0.1f Amp \n\n',I)
+printf('\n\n The motor output voltage =%0.1f Volts\n\n',Va)