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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+// variable Initialization
+Vm=208 //Supply Voltage In Volts
+af=0 //Firing Angle Of Converters In Field
+Rf=147 //Field Resistance In Ohm
+Ra=0.25 //Armature Resistance In Ohm
+T=45 //Load Torque In N-m
+Kv=0.7032 //Motor Voltage Constant
+N=1000 //Motor Speed In Rpm
+
+//Solution
+Vf=Vm*(1+cos(af))*(1/%pi)*1.414 //Voltage Across Field In Volts
+If=Vf/Rf //Field Current In Amp
+Ia=T/(Kv*If) //Armature Current In Amp
+w=(2*%pi*N)/60 //Angular Speed In Rad/Sec
+Eb=Kv*If*w //Back Emf In Volts
+Va=Eb+Ia*Ra //Voltage Across Armature In Volts
+A=%pi*Va*(1/Vm)*(1/1.414)
+aa=acosd(A-1) //Delay Angle Of Semi Converter In Armature Circuit
+VaIa=Va*Ia //Power Output Of Converters In Armature Circuit In Watts
+I=sqrt((180-aa)*(1/180))*Ia //Input Current
+VA=Vm*I //Input VA
+Pf=VaIa/VA //Input Power Factor
+
+//Result
+printf('\n\n The Field Current=%0.1f Amp\n\n',If)
+printf('\n\n The Delay Angle Of Semi Converter In Armature Circuit=%0.1f degree\n\n',aa)
+printf('\n\n The Power Factor Of Semi Converter In Armature Circuit=%0.1f\n\n',Pf)
+//The answers vary due to round off error(2nd and 3rd)