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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3784/CH1/EX1.12/Ex1_12.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3784/CH1/EX1.12/Ex1_12.sce')
| -rw-r--r-- | 3784/CH1/EX1.12/Ex1_12.sce | 23 |
1 files changed, 23 insertions, 0 deletions
diff --git a/3784/CH1/EX1.12/Ex1_12.sce b/3784/CH1/EX1.12/Ex1_12.sce new file mode 100644 index 000000000..8ef38d764 --- /dev/null +++ b/3784/CH1/EX1.12/Ex1_12.sce @@ -0,0 +1,23 @@ +clc
+// Variable Initialization
+Vm=230//Supply Voltage in Volts
+Ra=0.3//Armature circuit resistance in Ohm
+I=18 //Rated current in Amp
+Nr=1500 //Motor speed in Rpm
+a=45//firing angle in Degree
+Vs=220 //input in volts
+
+//Solution
+Va=(2*Vm*1.414)*cosd(a)*(1/%pi)//Average voltage in Volts
+Eb=Va-(I*Ra)//Back emf in volts
+//When the polarity of the back emf is reversed ,the machine would act as generator and hence the governing equation
+Va=-Eb+(I*Ra) //Armature voltage in volts
+af=acosd((Va*%pi)/(2*Vs*sqrt(2)))//Firing angle in Degree(This value is Wrongly calculated in Textbook)
+Pg=Eb*I //Power generated in Watt
+Pl=((I)^2)*Ra //Power loss in armature in Watt
+P=Pg-Pl //Power fed to the supply in Watt
+
+//Results
+printf('\n\n The Firing Angle=%0.1f Degree\n\n',af)
+printf('\n\n The Power fed back to Supply=%0.1f Watt\n\n',P)
+//The answer provided in the textbook is wrong(1st answer)
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