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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clear
+//Given
+M = 10 //KN-m moment
+v = 8.0 //KN - shear Stress
+stress_allow = 8 //MPa - The maximum allowable stress
+shear_allow_per = 1.4 //MPa - The allowable stress perpendicular to grain
+stress_allow_shear = 0.7 //MPa - The maximum allowable shear stress
+//Caliculations
+
+S = M*(10**6)/stress_allow //mm3
+//lets arbitarly assume h = 2b
+//S = b*(h**2)/6
+h = (12*S**0.333) //The depth of the beam
+b = h/2 //mm The width of the beam
+A = h*b //mm2 The area of the crossection , assumption
+stress_shear = 3*v*(10**3)/(2*A) //MPa The strear stress
+if stress_shear<stress_allow_shear then
+ printf("The stress developed %0.2f is in allowable ranges for %0.2f mm2 area",stress_shear,A)
+else
+ printf("The stress developed %0.3f is in non allowable ranges %0.3f area",stress_shear,A)
+ end
+Area_allow = v*(10**3)/shear_allow_per //mm - the allowable area
+printf("\n The minimum area is %0.3f mm2",Area_allow )