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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
commit7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch)
treedbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3776/CH7
parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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-rw-r--r--3776/CH7/EX7.1/Ex7_1.sce23
-rw-r--r--3776/CH7/EX7.2/Ex7_2.sce23
-rw-r--r--3776/CH7/EX7.6/Ex7_6.sce15
-rw-r--r--3776/CH7/EX7.8/Ex7_8.sce18
-rw-r--r--3776/CH7/EX7.9/Ex7_9.sce23
5 files changed, 102 insertions, 0 deletions
diff --git a/3776/CH7/EX7.1/Ex7_1.sce b/3776/CH7/EX7.1/Ex7_1.sce
new file mode 100644
index 000000000..22b3a758c
--- /dev/null
+++ b/3776/CH7/EX7.1/Ex7_1.sce
@@ -0,0 +1,23 @@
+clear
+//Given
+shear_v = 3000 //N - Transmitted vetical shear
+shear_al = 700 //N - The maximum allowable
+//We will divide this into two parts
+l_1 = 50.0 //mm
+l_2 = 200.0 //mm
+b_1 = 200.0 //mm
+b_2 = 50.0 //mm
+A_1 = l_1* b_1 //mm2 - area of part_1
+y_1 = 25.0 //mm com distance
+A_2 =l_2*b_2 //mm2 - area of part_1
+y_2 = 150.0 //in com distance
+y_net = (A_1*y_1 +A_2*y_2)/(A_1+A_2) //mm - The com of the whole system
+c_max = (4-y_net) //mm - The maximum distace from com to end
+c_min = y_net //mm - the minimum distance from com to end
+I_1 = b_1*(l_1**3)/12 + A_1*((y_1-y_net)**2) //Parallel axis theorm
+I_2 = b_2*(l_2**3)/12 + A_2*((y_2-y_net)**2)
+I_net = I_1 + I_2 //mm4 - the total moment of inertia
+Q = A_1*(-y_1+y_net) //mm3
+q = shear_v*Q/I_net //N/mm - Shear flow
+d = shear_al/q // The space between the nails
+printf("\n The minimal space between the nails %0.1f mm",d)
diff --git a/3776/CH7/EX7.2/Ex7_2.sce b/3776/CH7/EX7.2/Ex7_2.sce
new file mode 100644
index 000000000..71c8e8755
--- /dev/null
+++ b/3776/CH7/EX7.2/Ex7_2.sce
@@ -0,0 +1,23 @@
+clear
+//Given
+l = 6 //m -length of the beam
+p = 3 //KN-m _ the load applied
+R_a = l*p/2 //KN -The reaction at a, Since the system is symmetry
+R_b = l*p/2 //KN -The reaction at b
+l_s = 10 //mm - The length of the screw
+shear_al = 2 //KN - The maximum load the screw can take
+I = 2.36*(10**9) //mm2 The moment of inertia of the whole system
+//We will divide this into two parts
+l_1 = 50.0 //mm
+l_2 = 50.0 //mm
+b_1 = 100.0 //mm
+b_2 = 200.0 //mm
+A_1 = l_1* b_1 //in2 - area of part_1
+y_1 = 200.0 //mm com distance
+A_2 =l_2*b_2 //mm2 - area of part_1
+y_2 = 225.0 //in com distance
+Q = 2*A_1*y_1 + A_2*y_2 // mm**3 For the whole system
+q = R_a*Q*(10**3)/I //N/mm The shear flow
+d = shear_al*(10**3)/q //mm The space between the nails
+printf("\n The minimal space between the nails %0.0f mm",d)
+printf("\n Similar calculation for 4.5 KN gives spacing of 246mm")
diff --git a/3776/CH7/EX7.6/Ex7_6.sce b/3776/CH7/EX7.6/Ex7_6.sce
new file mode 100644
index 000000000..89fca203f
--- /dev/null
+++ b/3776/CH7/EX7.6/Ex7_6.sce
@@ -0,0 +1,15 @@
+clear
+//Given
+//we will divide this into two equal parts and other part
+l = 10.0 // in - The height
+t = 0.1 // in - The width
+b = 5.0 //mm- The width of the above part
+A = t* b //in2 - area of part
+y_net = l/2 // The com of the system
+y_1 = l // The position of teh com of part_2
+I_1 = t*(l**3)/12 //in^4 The moment of inertia of part 1
+I_2 = 2*A*((y_1-y_net)**2) //in^4 The moment of inertia of part 2
+I = I_1 + I_2 //in^4 The moment of inertia
+e = (b**2)*(l**2)*t/(4*I) //in the formula of channels
+l_sc = e - t/2 //in- The shear centre
+printf("\n The shear centre from outside vertical face is %0.3f in",l_sc )
diff --git a/3776/CH7/EX7.8/Ex7_8.sce b/3776/CH7/EX7.8/Ex7_8.sce
new file mode 100644
index 000000000..67646ba58
--- /dev/null
+++ b/3776/CH7/EX7.8/Ex7_8.sce
@@ -0,0 +1,18 @@
+clear
+//Given
+dia = 10.0 //mm - The diameter of the cylinder
+c = dia/2 //mm - the radius of the cylinder
+A = 3.14*(c**2) //mm2 The area of the crossection
+y = 4*c/(3*3.14) //mm The com of cylinder
+I = 3.14*(c**4)/4 //mm4 - The moment of inertia of the cylinder
+j = 3.14*(dia**4)/32 //mm4
+T = 20.0 //N.m - The torque
+V = 250.0 //N - The shear
+M = 25.0 //N-m The bending moment
+Q = A*y/2 //mm
+stress_dmax = 4*V/(3*A) //V*Q/(I*d) //MPa The direct maximum stress
+stress_tmax = T*c*(10**3)/j //-MPa The torsion maximum stress
+stress_total = stress_dmax + stress_tmax //MPa The total stress
+printf("\n The direct maximum stress %0.2f MPa",stress_dmax)
+printf("\n The torsion maximum stress %0.2f MPa",stress_tmax)
+printf("\n The total stress %0.2f MPa",stress_total)
diff --git a/3776/CH7/EX7.9/Ex7_9.sce b/3776/CH7/EX7.9/Ex7_9.sce
new file mode 100644
index 000000000..4822c44e0
--- /dev/null
+++ b/3776/CH7/EX7.9/Ex7_9.sce
@@ -0,0 +1,23 @@
+clear
+//Given
+dia = 15 //mm - The diameter of the rod
+h = 0.5 //mt - The freely falling height
+A = 3.14*(dia**2)/4 //mm2 The area of the crossection
+E = 200 //Gpa -Youngs modulus
+L = 750 //mm - The total length of the rod
+G = 80 //gpa - Shear modulus
+N = 10 //number of live coils
+d = 5 //mm the diameter of live coil
+m = 3 // the mass of freely falling body
+H = 500 //mm -from mass to spring
+F= m*9.81 //Kg the force due to that mass
+p = 3 //KN-m _ the load applied
+//e = e_rod + e_spr
+//e_rod
+e_rod = p*L*(10**-3)/(A*E) //mm The elongation due to freely falling body
+//e_spr
+e_spr = 64*F*(dia**3)*N*(10**-3)/(G*(d**4)) //mm The elongation due to spring
+e = e_rod + e_spr //mm The total elongation
+p_dyn =F*(1+((1+(2*H/e))**0.5))
+Stress_max = p_dyn/A //MPa - The maximum stress in the system
+printf("\n The maximum stress in the system %0.2f MPa",Stress_max)