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+// exa 5.6 Pg 153
+clc;clear;close;
+
+// Given Data
+n=5;// no. of rivets
+P=45;// kN
+alfa=30;// degree
+tau=120;// MPa
+
+
+Pd=P/n*1000;// N (direct shear load in rivet)
+// C.G. of rivet group
+// values below are collected direct from figure
+x_bar=(3*200)/5;// mm
+y_bar=(1*50+1*150+1*100+1*200)/5;// mm
+ex=300+x_bar+y_bar;//mm
+ey=100;//mm
+l1=sqrt(x_bar**2+(y_bar/2)**2);// mm
+l2=l1;//mm
+l3=sqrt(100**2+80**2);// mm
+l4=80;//mm
+l5=l3;//mm
+
+//2*F1*l1+2*F3*l3+F4*l4=P*cos(alfa)*ex+P*sin(alfa)*ey
+F1=(P*1000*cosd(alfa)*ex+P*1000*sind(alfa)*ey)/(2*l1**2+2*l3**2+l4**2)*l1;//N
+// rivet 1 is nearest
+Beta = atand(x_bar/(y_bar/2));// degree
+theta1=Beta-(90-alfa);// degree
+R1=sqrt(Pd**2+F1**2+2*Pd*F1*cosd(theta1));// N (resultant force in rivet 1)
+//R1=%pi/4*d0**2*tau
+d0=sqrt(R1/(%pi/4*tau));// mm
+printf('\n diameter of rivets = %.2f mm. Use d0 = 21.5 mm & d=20 mm for design.',d0)
+// Note -  Ans in the textbook is wrong.