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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
commit7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch)
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parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+// exa 3.8 Pg 70
+
+clc;clear;close;
+
+// Given Data
+M=15;// N.m
+P=5;// kW
+N=500;// rpm
+tau_d=40;// Mpa
+sigma_d=58;// MPa
+
+T=P*60*10**3/(2*%pi*N);// N.m
+Te=sqrt(M**2+T**2);// N.m
+//Te=(%pi/16)*d**3*tau_d
+d=(Te/((%pi/16)*tau_d)*1000)**(1/3);// mm
+printf('\n Using equivalent torque equation,\n shaft diameter d = %.f mm',d)
+
+Me=(1/2)*(M+sqrt(M**2+T**2));// N.m
+//Me=(%pi/32)*d**3*sigma_d
+d=(Me/((%pi/32)*sigma_d)*10**3)**(1/3);//mm
+printf('\n Using equivalent bending moment equation,\n shaft diameter d = %.2f mm or %.f mm',d, ceil(d))
+printf('\n Adopt d=23 mm.')