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+// Problem no 7.8,Page no.189
+
+clc;clear;
+close;
+
+L_BC=1.8 //m //Length of BC
+L_AB=1.2 //m //Length of AB
+sigma_s=70 //MPa //shear stress
+d_1=0.05 //m //diameter of BC
+d_2=0.1 //m //diameter of AB
+r_BC=0.025 //cm //Radius of BC
+
+//Calculations
+
+I_p_BC=%pi*32**-1*d_1**4 //m**4 //Polar M.I of BC
+I_p_AB=%pi*32**-1*d_2**4 //m**4 //Polar M.I od AB
+
+//For BC
+//theta_1=T*L_BC*(G*10**9*I_p_BC)**-1 //Angle of Twist of C relative to B
+//After substituting and simplifying value, we get
+
+//theta_1=3.4923*10**-5*T
+
+//For AB
+//theta_2=T*L_AB*(G*10**9*I_p_AB)**-1 //Angle of Twist of B relative to A
+//After substituting and simplifying value, we get
+
+//theta_2=1.45513*T
+
+//sigma_s=T*R*(I_P)**-1 //The max shear stress in BC
+
+//After substituting and simplifying value in above equation, we get
+
+T=sigma_s*10**6*I_p_BC*r_BC**-1 
+theta_1=3.4923*10**-5*T
+theta_2=1.45513*10**-6*T
+theta_c=theta_1-theta_2 //radian //total angle of twist
+
+//Result
+printf("Total angle of Twist is %.3f radian",theta_c)