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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Problem no 6.14,Page No.168
+
+clc;clear;
+close;
+
+L=10 //m //Lenght of cantilever beam
+P_1=20*10**3 //N //Load at free end
+P_2=20*10**3 //N //Load at middle of beam
+E=200*10**9 //Pa
+I=20000*10**-8 //m**4
+
+//Calculations
+
+//Taking moment at pt B we get
+R_a=20*5*10**-1 //Force at pt A
+
+//Now B.M at b=0,at C=-100,at A=-300 KN*m
+
+//Now Area of B.M
+A_1=2**-1*5*100 //KN*m**2
+A_2=5*100 //KN*m**2
+A_3=2**-1*5*200 //KN*m**2
+
+//Total Area of B.M diagram is given by A
+A=A_1+A_2+A_3
+
+theta=A*10**3*(E*I)**-1 //radian
+
+x_1=2*3**-1*5
+x_2=3*2**-1*5
+x_3=5*3**-1*5
+M_1=A_1*x_1
+M_2=A_2*x_2
+M_3=A_3*x_3
+
+M=M_1+M_2+M_3 //Total moments of B.M about B
+
+y_B=M*10**3*(E*I)**-1 //Deflection a tfree end
+
+//REsult
+printf("Slope of cantilever at free end is %.2f",theta);printf(" radian")
+printf("\n Deflection of cantilever at free end is %.2f",y_B);printf(" m")