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+// Problem 5.9,Page no.128
+
+clc;clear;
+close;
+
+B=24 //mm //width of beam section
+D=21.7 //mm //depth of beam section
+E_1=11440 //MN/m**2 //Modulus of Elasticity parallel grain
+E_2=2860 //MN/m**2 ////Modulus of Elasticity perpendicular grain
+sigma_1=8.57 //MN/m**2
+sigma_2=2.14 //MN/m**2
+L=1.2 //m //span of beam
+
+//Calculations
+
+//Ratio of smaller modulus to larger modulus is E_2:E_1=1:4
+//Dimension of transformed Beam section
+b=18 //mm //width of Beam section
+d=3.1 //mm //depth of beam section
+
+I=(1*12**-1*B*10**-3*(D*10**-3)**3)-(3*(1*12**-1*b*10**-3*(d*10**-3)**3)) //m**4 //M.I of transformed section
+y=21.7*10**-3*2**-1 
+M=I*sigma_1*10**6*y**-1 //N*m //Safe B.M
+P=4*M*L**-1 //N
+
+//Result
+printf("Safe value of Load is %.2f N",P)