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+// Problem 5.11,Page no.131
+
+clc;clear;
+close;
+
+D=4 //cm //Outside diameter
+d=3 //cm //inside diamter
+L=2 //m //span of beam
+W=1000 //N //Max safe Load
+
+//Calculations
+
+I=%pi*64**-1*(D**4-d**4) //cm**4 //M.I
+A=%pi*4**-1*(D**2-d**2) //cm**2 //Area 
+y=2 
+Z=I*y**-1 //cm**3 //Section modulus
+
+M=W*L*4**-1 //N*cm //Max bending moment
+
+//From Flexural Formula
+sigma=M*Z**-1 //N/cm**2
+
+//For Tubes
+//M.I about x-x axis
+I_1=4*(8.59+5.492*2**2) //cm**4 
+
+Z_1=122.32*4**-1 //cm**3 
+
+//M=W_1*200*4**-1 //N*cm
+//After substituting values we get
+//M=50*W_1 (equation 1)
+
+//Again from Flexural Formula
+M=sigma*Z_1
+
+//substitute value of M in equation 1
+
+W=11640*30.58*50**-1 //N
+
+//Result
+printf("Max central load is %.2f N",W)