initial commit / add all books

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diff --git a/3772/CH17/EX17.1/Ex17_1.sce b/3772/CH17/EX17.1/Ex17_1.sce
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+//Ex no.17.1,Page no.379
+
+clc;
+clear;
+close;
+//Initilization of Variables
+
+b=12 //cm //width of steel plates
+t=1 //cm //thickness of steel plates
+sigma=75 //MPa //stress
+
+//Calculations
+
+//The maximum Load which the plate can carry
+P=b*t*10**-6*sigma*10**6 //N 
+
+//Length of weld for static loading
+
+//size of weld is equal to thickness of plate
+S=t //cm
+
+//P=2**0.5*l*S*sigma
+
+//After substituting values and simplifying above equation, we get, 
+l=((P)*(2**0.5*S*sigma)**-1) //cm
+
+//add 1.25 to allow start and stop of weld run
+L=l+1.25 //cm 
+
+//Length of weld for Dynamic loading
+
+//The stress concentration factor for transverse fillet weld is 1.5
+
+sigma_2=sigma*1.5**-1 //MPa //Permissible tensile stress
+
+//P=2**0.5*l_2*S*sigma_2 
+
+//After substituting values and simplifying above equation, we get,
+l_2=((P)*(2**0.5*S*sigma_2)**-1) //cm
+
+//add 1.25 cm
+l_3=l_2+1.25 //cm 
+
+//Result
+printf("Length of weld for static loading = %.2f cm",L)
+printf("\n Length of weld for Dynamic loading = %.3f cm",l_3)
diff --git a/3772/CH17/EX17.2/Ex17_2.sce b/3772/CH17/EX17.2/Ex17_2.sce
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index 000000000..2f01dd612
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+//Ex no.17.2,Page no.380
+clc;
+clear;
+close;
+
+//Initilization of Variables
+
+d=6 //cm //diameter of rod
+L=40 //cm //Length of steel plate
+P=12 //KN //Load
+sigma=180 //MPa //Allowable stress
+
+//Calculations
+
+A=%pi*4**-1*d**2 //cm**2 //Area of rod
+M=P*10**3*L //Ncm
+
+F=M*A**-1 //N/cm //Force per unit cm of weld at top and bottom
+
+V_s=P*10**3*(%pi*d)**-1 //N/cm //vertical shear
+
+R=(F**2+V_s**2)**0.5 //N/cm //resultant Load
+
+S=R*(sigma)**-1*10**-2 //cm //size of weld
+
+//Result
+printf("Size of weld is %.2f cm",S)
diff --git a/3772/CH17/EX17.3/Ex17_3.sce b/3772/CH17/EX17.3/Ex17_3.sce
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index 000000000..e72057275
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+//Ex no.17.3,Page no.380
+clc;clear;close;
+
+//Initilization of Variables
+
+b=12 //cm //width of plate
+S=1;t=1 //cm //thickness of plate
+P=50 //KN //load
+sigma_s=60 //MPa //shear stress
+
+//Calculations (part-1)
+
+//Under static Loading
+
+//P=2**0.5*l*S*sigma_s
+
+l=((P*10**3)*(2**0.5*S*sigma_s*10**-4*10**6)**-1) //cm 
+
+//add 1.25 cm to start and stop weld run
+
+L=l+1.25 //cm //length of weld
+
+//Calculations (part-2)
+
+//Under Fatigue load
+
+//stress concentration factor for parallel fillet weld is 2.7
+
+sigma_s_2=sigma_s*2.7**-1 //MPa //permissible shear stress
+
+//P=2**0.5*l_2*S*sigma_s_2
+
+l_2=((P*10**3)*(2**0.5*S*sigma_s_2*10**-4*10**6)**-1) //cm
+
+//add 1.25 cm 
+
+l_3=l_2+1.25 //cm //length of weld
+
+//Result
+printf("Length of weld Under static Loading is %.3f cm",L)
+printf("\n Length of weld Under Ftigue Loading is %.3f cm",l_3)
diff --git a/3772/CH17/EX17.4/Ex17_4.sce b/3772/CH17/EX17.4/Ex17_4.sce
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index 000000000..e94684465
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+++ b/3772/CH17/EX17.4/Ex17_4.sce
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+//Ex no.17.4,Page no.381
+clc;clear;close;
+
+//Initilization of Variables
+
+sigma_t=100 //MPa //tensile stress
+P=170 //KN //Load
+
+//Calculations
+
+//For equal stress in the welds A and B, the load shared by the fillet welds will be proportional to size of weld
+
+//t_a=0.7*s //Effective throat thickness of weld A in upper plate
+//s=size of weld 
+
+//t_b=1.05*s //Effective throat thickness of weld B in lower plate
+
+//For weld A
+//P_1=l*t*sigma_t 
+
+//After substituting values and simplifying above equation, we get,
+//P_1=84000*s //N     (equation 1)
+
+//P_2=l*t_2*sigma_t
+
+//After substituting values and simplifying above equation, we get,
+//P_2=126000*s //N     (equation 2)
+
+//After adding equation 1 and 2, we get,
+//P=210000*s           (equation 3)
+
+//Now equating total forces of the fillets to load on the plates
+s=P*10**3*210000**-1 //cm
+
+//Result
+printf("size of end fillet is %.2f cm",s)
diff --git a/3772/CH17/EX17.5/Ex17_5.sce b/3772/CH17/EX17.5/Ex17_5.sce
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index 000000000..9fadc2b4d
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+++ b/3772/CH17/EX17.5/Ex17_5.sce
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+//Ex no.17.5,Page no.381
+clc;clear;close;
+
+//Initilization of Variables
+
+L_1=30 //cm //length of longitudinal weld
+L_2=16 //cm //length of transverse weld
+//t=0.7*s //Effective thickness of weld 
+sigma_t_1=100 //MPa //working stress for transverse welds
+sigma_t_2=85 //MPa //working stress for longitudinal welds
+P=150 //KN //load
+
+//Calculations
+
+//For transverse weld
+//P_1=L_1*t*10**-4*sigma_t_1*10**6 
+
+//After substituting values and simplifying above equation, we get,
+//P_1=112000*s //N
+
+//For longitudinal weld
+//P_2=L_2*t*10**-4*sigma_t_2*10**6
+
+//Total force of resistance of weld
+//P=P_1+P_2 //N
+
+//after adding we get,
+//P=290500*s //N
+
+//Now equating total forces of resistance to pull of the joint
+s=P*10**3*290500**-1 //cm
+
+//Result 
+printf("size of weld is %.3f cm",s)
diff --git a/3772/CH17/EX17.6/Ex17_6.sce b/3772/CH17/EX17.6/Ex17_6.sce
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index 000000000..2b90f9088
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+//Ex no.17.6,Page no.382
+clc;clear;close;
+
+//Initilization of Variables
+
+P=200 //KN //Load carried by the angle 
+S=0.6 //mm //size of weld
+b=4.46 //cm //Distance of centre of gravity of the angle from the top shorter leg
+a=10.54 //cm //Distance of centre of gravity of the angle from the top edge of the angle
+sigma_s=102.5 //MPa //shear stress
+//l_1=Length of the top weld
+//l_2=length of the bottom weld
+//L=l_1+l_2 //cm //total length weld
+
+//Using the relation
+//P=L*0.7*S*sigma_s
+
+//After substituting values and simplifying we get
+L=(P*10**3)*(0.7*S*sigma_s*10**-4*10**6)**-1 //cm  (equation 1)
+
+//Using the relation
+l_1=(L*b)*(a+b)**-1 //cm
+
+//substituting this value in equation 1 we have,
+l_2=L-l_1 //cm 
+
+//Result
+printf("Distance of centre of gravity of the angle from the top edge of the angle = %.2f cm",l_2)
diff --git a/3772/CH17/EX17.7/Ex17_7.sce b/3772/CH17/EX17.7/Ex17_7.sce
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+//Ex no.17.7,Page no.383
+clc;clear;close;
+
+//Initilization of Variables
+
+P=12 //KN //Load
+sigma_s=75 //N/mm**2 //shear stress
+e=12 //cm
+r_1=2.5 //cm
+
+//Calculations
+
+//A=(2*S*l)*(2)**0.5
+//sigma_s=P*A**-1 //MPa //shear stress
+
+//After substituting values and simplifying we get
+//sigma_s=16.97*S**-1 //MPa
+
+//I_g=S*l*(3*b**2+l**2)*(6)**-1 //cm**4 //Polar moment of Inertia of weld
+
+//After substituting values and simplifying we get
+//I_g=180.833*S //cm**4
+r_2=((8*2**-1)**2)+((5*2**-1)**2)**0.5 //cm //max radius of weld
+
+//sigma_s_2=P*e*r_2*I_g**-1 //MPa //shear stress due to bending moment
+
+cos_theta=r_1*r_2**-1
+
+//Now using the relation
+//sigma_s=(sigma_s_1**2+sigma_s_2**2+2sigma_s_1*sigma_s_2*cos_theta
+
+S=(2363.8958*5625**-1)**0.5 //cm //size of the weld
+
+//Result
+printf("size of the weld = %.3f cm",S)