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+// Problem 16.2,Page no.367
+
+clc;clear;
+close;
+
+p=7.5 //cm //%pitch of rivets
+t=1.5 //cm //Thickness of plate
+d=2.5 //cm //diameter of rivets
+sigma_t=400 //MPa //Working stress
+sigma_c=640 //MPa //crushing stress
+sigma_s=320 //MPa //shearing stress
+n=2 //No. of rivets
+
+//Calculation
+
+P_t=(p-d)*t*10**-4*sigma_t*10**6*10**-3 //kN //Strength of plate in tearing
+P_s=n*%pi*4**-1*d**2*10**-4*sigma_s*10**6*10**-3 //kN //Shearing strength
+P_c=n*d*t*10**-4*sigma_c*10**6*10**-3 //kN //crushing strength
+
+//Thus Minimum force that will rapture the joint is least of P_t,P_s,P_c i.e P_t
+
+//Result
+printf("Minimum force that will rapture the joint is %.2f",P_t);printf(" kN")