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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Problem no 14.3,Page No.327
+
+clc;clear;
+close;
+rho_w=10 //KN/m**3 //Density of water
+rho_mason=22.4 //KN/m**3 //Density of mason
+H=6 //m //height of dam
+a=1 //m //width of top
+b=4 //m //bottom width
+h=5.5 //m //Weight of water depth
+
+//Calculations
+
+//Let L=1 m (length of dam)
+L=1
+
+//weight of dam
+W=(a+b)*2**-1*H*a*rho_mason
+
+//Lateral thrust
+P=rho_w*h**2*a*2**-1
+
+//distance of Line of action of W measured from vertical face
+x_bar=(b**2+b*a+a**2)*(3*(b+a))**-1
+
+//distance of pt where resultant cuts the base
+x=P*W**-1*h*3**-1
+
+//Eccentricity
+e=x_bar+x-b*2**-1
+
+//Stress at Pt B
+sigma1=W*b**-1*(1-6*e*b**-1)
+
+//stress at Pt C
+sigma2=W*b**-1*(1+6*e*b**-1)
+
+//Result
+printf("Max stress intensities at the base is %.2f",sigma2);printf(" KN/m**2")
+printf("\n Min stress intensities at the base is %.2f",sigma1);printf(" KN/m**2")
+
+//Plotting the Shear Force Diagram
+
+X1=[0,L,L]
+Y1=[sigma2,sigma1,0]
+Z1=[0,0,0]
+plot(X1,Y1,X1,Z1)
+xlabel("Length x in m")
+ylabel("Shear Force in kN")
+title("the Shear Force Diagram")