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+// Problem no 13.2,Page No.301
+
+clc;clear;
+close;
+//W=10*w //KN/m //u.d.l
+sigma=805*10**6 //Pa  //Bending stress
+Tou=0.85*10**6 //Pa //Shear stress
+
+//Calculations
+
+//M=W*L**2*10**-4*8**-1 //Max B.M
+//F=W*L*10**-2*2**-1 //Max S.F
+//y=h*2**-1 //depth
+//A-b*h //Area of c/s
+
+//Now using relation we get
+//sigma=M*h*(2*I)**-1   //Bending stress
+
+//AFter substituitng values we get
+//805*10**6=w*l**2*h*(16*10**5*I)**-1   //Equation 1
+
+//Again using the relation we get 
+//tou=F*A*y_bar*(I*b)**-1  //shear atress
+
+//AFter substituitng values we get
+//0.85*10**6=w*L*h**2*(16*10**5*I)**-1  //Equation 2
+
+//Dividing equation 1 & 2 we get
+//L*h**-1=10
+//Let L*h**-1=Z
+z=10
+
+//Result
+printf("The Ratio of span to depth ratio is %.2f",z)