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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
commit7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch)
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parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+
+clc;
+Pm=60000;
+P=6;
+s=0.04;
+V=400;
+smT=0.2;
+f=50;
+Ns=(120*f)/P;
+
+Ws=(2*%pi*Ns)/60;
+Wr=Ws*(1-s);
+Tefl=Pm/Wr;
+
+//for part a
+Tem=(((smT/s)+(s/smT))/2)*Tefl;
+mprintf('for part a \n the maximun torque is %f Nm\n',Tem);
+
+//for part b
+Prot=(s/(1-s))*(Pm);
+mprintf('for part b \n the rotor ohmic loss is %f W\n',Prot);
+
+//for part c
+smT1=2*smT;
+mprintf('for part c \n THe new slip is %f \n',smT1);
+
+//for part d
+//On analysis the slip is given by
+s2=0.084;
+mprintf('for part d \n full load slip is %f \n',s2);
+
+//for part e
+T2=Pm/((Ws)*(1-s2));
+mprintf('for part e \n the full load torque is %f Nm\n',T2);
+
+
+
+
+
+