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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+clc;
+v=2200; // rated voltage of motor
+r=0.32; // per phase armature resistance
+p=1500; // KW rating of motor
+ie=15; // exciting current
+is=750; // short circuit current
+cl=60; // core loss in KW
+fl=40; // frictional and windage loss in KW
+IF=[5 10 15 20 25 30];
+EFO=[ 760 1500 2140 2650 3040 3340]; // excitation EMF per phase
+EFP=EFO/sqrt(3);
+disp('Excitation EMF per phase(V) is');
+disp(EFP);
+// from table given for ie=15,
+Ef=2140; // Excitation EMF
+np=3; // number of phases
+ef=Ef/sqrt(3); // per phase open circuit voltage
+zs=ef/is; // synchronous impedance
+vt=floor(v/sqrt(3)); // per phase terminal voltage
+i=floor(vt/zs); // current phasor lagging vt
+ia=vt/(2*r); // armature current
+pd=((p/2)+cl+fl)/np; // mechanical power developed per phase at half-full load output
+R=ceil(sqrt((ia^2-((pd*1000)/r))));
+printf('Radius of power circle is %f A\n',R);
+printf('Current phasor is %f A\n',i);
+printf('Synchronous impedance is %f ohm\n',zs);
+disp('using above data and table given in solution, V-curves and variation of p.f. with field currents can be plotted');