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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3760/CH4/EX4.31/Ex4_31.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3760/CH4/EX4.31/Ex4_31.sce')
-rw-r--r-- | 3760/CH4/EX4.31/Ex4_31.sce | 35 |
1 files changed, 35 insertions, 0 deletions
diff --git a/3760/CH4/EX4.31/Ex4_31.sce b/3760/CH4/EX4.31/Ex4_31.sce new file mode 100644 index 000000000..dc65331df --- /dev/null +++ b/3760/CH4/EX4.31/Ex4_31.sce @@ -0,0 +1,35 @@ +clc;
+Vt=230;//Supply voltage
+P=4;//No of poles
+A=2;//No of parallel paths for armature conductors
+Z=600;//No of armature conductors
+Ra=0.25;//armature circuit resistance in ohm
+phi=0.01;//flux per pole in weber
+Pr=500;//rotational losses in watts
+//generated emf in armature, Ea=(phi*Z*P*n)/(60*A) if n is speed in armature
+//Counter emf is Ea=(0.01*600*4*n)/(60*2)=0.2n volts
+//Vt=Ea+Ia*Ra
+//Ia=(Vt-Ea)/Ra/
+//Shaft o/p in watts, Psh=Ea*Ia-Pr, Psh=(0.2n)*(920-0.8n)-500 ....(1)
+n=[700 800 900 1000 1100];//different speeds of motor for which the shaft o/p power is to be measured
+//Psh=(0.184*n)-(1.6*(10e-4)*n*n)-0.5, Shaft o/p power in KW.
+Psh1=49.1;//Shaft o/p power in KW at n=700 rpm
+Psh2=44.3;//Shaft o/p power in KW at n=800 rpm
+Psh3=33.5;//Shaft o/p power in KW at n=900 rpm *Psh1,Psh2,Psh3,Psh4,Psh5 are calclulated from equation (1)*
+Psh4=23.5;//Shaft o/p power in KW at n=1000 rpm
+Psh5=8.3;//Shaft o/p power in KW at n=1100 rpm
+Psh=[Psh1 Psh2 Psh3 Psh4 Psh5];
+Pi=[4.5 8.5 14 21.1 30];//i/p power supplied to fan in KW.
+plot(n,Psh,n,Pi);xlabel('RPM');ylabel('KW');//Shaft o/p power versus speed of motor and power i/p versus speed of fan are plotted on the same graph
+//For plot :-*blue line- motor characteristic,green line- fan charactestic*
+//The intesecton of these two curves is called as OPERATING POINT.
+//At operating point the speed is 1012 rpm & pwer o/p of motor or power i/p to the fan is 22 KW ....(from the intersection point of two curves)
+n_=1012;//speed at operating point
+P_o=22000;//Power output loss
+Ia=920-(0.8*n_);//armature current
+Parm=Ia*Ia*Ra;//armature loss
+P_ip=P_o+Pr+Parm;//Power input
+%n=(P_o/P_ip)*100;//motor efficiency
+printf('Armature current is %f A\n.',Ia);
+printf('Operating speed is %f rpm\n.',n_)
+printf('Motor efficiency is %f percent.',%n);
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