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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc;
+//Armature reaction is neglected.
+Vt=250;//Supply voltage
+P=4;//No of poles
+A=2;//No of parallel paths for armature conductors
+Z=500;//No of armature conductors
+Ra=0.25;//armature circuit resistance in ohm
+Rf=125;//field resistance in ohm
+phi=0.02;//flux per pole in weber
+Il=14;//current drawn by motor from supply mains
+Ish=Vt/Rf;//constant shunt field current
+Pr=300;//rotational losses in watts
+Pi=Vt*Il;//power input in watts
+
+//PART(a)-
+Ia=Il-Ish;//armature current
+Ea=Vt-Ia*Ra;//counter/back emf
+//Ea=(P*phi*Z*N)/(60*A)
+N=(60*A*Ea)/(P*phi*Z);//speed of rotation of motor in rpm
+Wm=(2*%pi*N)/60;//angular velocity of motor
+Pe=Ea*Ia;//electromagnetic power
+Ti=Pe/Wm;//Internal torque developed in Nm.
+printf('Speed of rotation of motor is %f rpm.',N);
+printf('\nInternal torque developed = %f Nm.',Ti);
+
+//PART(b)-
+Psh=Pe-Pr;//shaft power
+Tsh=Psh/Wm;//shaft torque
+%n=(Psh/Pi)*100;//percentage eficiency
+printf('\nShaft power = %f watts.',Psh);
+printf('\nShaft torque = %f Nm.',Tsh);
+printf('\nEfficiency of motor is %f percent.',%n);